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74HC20D Integrated Circuit Chip , Dual 4 input NAND gate IC Electronic Components

Anterwell Technology Ltd.
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    Buy cheap 74HC20D Integrated Circuit Chip , Dual 4 input NAND gate IC Electronic Components from wholesalers
     
    Buy cheap 74HC20D Integrated Circuit Chip , Dual 4 input NAND gate IC Electronic Components from wholesalers
    • Buy cheap 74HC20D Integrated Circuit Chip , Dual 4 input NAND gate IC Electronic Components from wholesalers
    • Buy cheap 74HC20D Integrated Circuit Chip , Dual 4 input NAND gate IC Electronic Components from wholesalers

    74HC20D Integrated Circuit Chip , Dual 4 input NAND gate IC Electronic Components

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    Brand Name : Anterwell
    Model Number : 74HC20D
    Certification : new & original
    Price : Negotiate
    Payment Terms : T/T, Western Union, Paypal
    Supply Ability : 8300pcs
    Delivery Time : 1 day
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    74HC20D Integrated Circuit Chip , Dual 4 input NAND gate IC Electronic Components


    74HC20D Integrated Circuit Chip , Dual 4 input NAND gate IC Electronic Components


    Dual 4-input NAND gate 74HC/HCT20


    FEATURES

    • Output capability: standard

    • ICC category: SSI


    GENERAL DESCRIPTION

    The 74HC/HCT20 are high-speed Si-gate CMOS devices and are pin compatible with low power Schottky TTL (LSTTL). They are specified in compliance with JEDEC standard no. 7A. The 74HC/HCT20 provide the 4-input NAND function.


    QUICK REFERENCE DATA

    GND = 0 V; Tamb = 25 °C; tr = tf = 6 ns

    SYMBOLPARAMETERCONDITIONSTYPICALUNIT
    HCHCT
    tPHL/ tPLHpropagation delay nA, nB, nC, nD to nYCL = 15 pF; VCC = 5 V813ns
    CIinput capacitance3.53.5pF
    CPDpower dissipation capacitance per packagenotes 1 and 22217pF

    Notes

    1. CPD is used to determine the dynamic power dissipation (PD in µW):

    PD = CPD × VCC2 × fi + ∑ (CL × VCC2 × fo) where:

    fi = input frequency in MHz

    fo = output frequency in MHz

    CL = output load capacitance in pF

    VCC = supply voltage in V

    ∑ (CL × VCC2 × fo) = sum of outputs

    2. For HC the condition is VI = GND to VCC

    For HCT the condition is VI = GND to VCC − 1.5 V




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